(-7+9q)(7+9q)=81q^2-49

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Solution for (-7+9q)(7+9q)=81q^2-49 equation: 


Simplifying
(-7 + 9q)(7 + 9q) = 81q2 + -49

Multiply (-7 + 9q) * (7 + 9q)
(-7(7 + 9q) + 9q * (7 + 9q)) = 81q2 + -49
((7 * -7 + 9q * -7) + 9q * (7 + 9q)) = 81q2 + -49
((-49 + -63q) + 9q * (7 + 9q)) = 81q2 + -49
(-49 + -63q + (7 * 9q + 9q * 9q)) = 81q2 + -49
(-49 + -63q + (63q + 81q2)) = 81q2 + -49

Combine like terms: -63q + 63q = 0
(-49 + 0 + 81q2) = 81q2 + -49
(-49 + 81q2) = 81q2 + -49

Reorder the terms:
-49 + 81q2 = -49 + 81q2

Add '49' to each side of the equation.
-49 + 49 + 81q2 = -49 + 49 + 81q2

Combine like terms: -49 + 49 = 0
0 + 81q2 = -49 + 49 + 81q2
81q2 = -49 + 49 + 81q2

Combine like terms: -49 + 49 = 0
81q2 = 0 + 81q2
81q2 = 81q2

Add '-81q2' to each side of the equation.
81q2 + -81q2 = 81q2 + -81q2

Combine like terms: 81q2 + -81q2 = 0
0 = 81q2 + -81q2

Combine like terms: 81q2 + -81q2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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